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If x + y -7 =0 and 3x + y -13 = 0. then ...

If `x + y -7 =0` and `3x + y -13 = 0`. then what is `4x^(2) + y^(2) + 4xy` equal to?

A

75

B

85

C

91

D

100

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first solve the system of linear equations given and then substitute the values of \(x\) and \(y\) into the expression \(4x^2 + y^2 + 4xy\). ### Step 1: Write down the equations We have the following two equations: 1. \(x + y - 7 = 0\) (Equation 1) 2. \(3x + y - 13 = 0\) (Equation 2) ### Step 2: Solve for \(y\) in terms of \(x\) From Equation 1, we can express \(y\) in terms of \(x\): \[ y = 7 - x \] ### Step 3: Substitute \(y\) into Equation 2 Now, we will substitute \(y\) from Step 2 into Equation 2: \[ 3x + (7 - x) - 13 = 0 \] Simplifying this gives: \[ 3x - x + 7 - 13 = 0 \] \[ 2x - 6 = 0 \] ### Step 4: Solve for \(x\) Now, we solve for \(x\): \[ 2x = 6 \implies x = \frac{6}{2} = 3 \] ### Step 5: Substitute \(x\) back to find \(y\) Now that we have \(x\), we can find \(y\): \[ y = 7 - x = 7 - 3 = 4 \] ### Step 6: Substitute \(x\) and \(y\) into the expression Now we substitute \(x = 3\) and \(y = 4\) into the expression \(4x^2 + y^2 + 4xy\): \[ 4x^2 + y^2 + 4xy = 4(3^2) + (4^2) + 4(3)(4) \] Calculating each term: \[ = 4(9) + 16 + 4(12) \] \[ = 36 + 16 + 48 \] ### Step 7: Combine the results Now we add these values together: \[ 36 + 16 + 48 = 100 \] ### Final Answer Thus, the value of \(4x^2 + y^2 + 4xy\) is \(100\). ---
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