Home
Class 14
MATHS
The ratio of time taken to run a certain...

The ratio of time taken to run a certain distance by Pythagoras and Hawkins is 4:3 and thus Hawkins wins the race by 360 m.What is the distance of race course?

Text Solution

Verified by Experts

The correct Answer is:
1440 m
Promotional Banner

Topper's Solved these Questions

  • TIME, SPEED AND DISTANCE

    ARIHANT SSC|Exercise INTRODUCTORY EXERCISE(9.1 )|3 Videos
  • TIME, SPEED AND DISTANCE

    ARIHANT SSC|Exercise EXERCISE LEVEL 1|150 Videos
  • TIME AND WORK

    ARIHANT SSC|Exercise Final Round|15 Videos
  • TRIGONOMETRY

    ARIHANT SSC|Exercise EXERCISE(LEVEL - 1)|35 Videos

Similar Questions

Explore conceptually related problems

The ratio of speeds of A anD B is 4:7 and A loses the race by 270 m then what is the length of the race course?

Time taken by A is 5/7 of B's time for the same length of race.The speed of A is 84 m/s and A betas B by 240 m.What is the length of the race course?

Time taken by A is 5/7 of B's time for the same length of race. The speed of A is 84 m/s and A beats B by 240 m. What is the length of race course?

The ratio between the rates of walking of A and B is 2 : 3. If the time taken by B to cover a certain distance is 48 minutes, the time taken (in minutes) by A to cover the distance is :

The ratio between the rates of walking of A and B is 2:3 if the time taken by B to cover a certain distance is 48 minutes the time taken(in minutes)by A to cover the distance is:

The ratio of speeds of X and Y is 5:6 . If Y allows X a start of 70m in a 1.2km race, then who will win the race and by what distance ?

Find the time taken by a car running at 25 m/s to cover a distance of 360 km (in hours)?