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In a survey among B - school students , ...

In a survey among B - school students , 68% of those surveyed were in favour of atleast one of the three magazines - A, B and C. 38% of those favoured , magazines - A, 26% favoured magazine B and 36% favoured magazine C . If 11% of those surveyed favoured more than one of the three magazine . What percent of those surveyed favoured more than one of the three magazines ?

A

0.25

B

0.33

C

0.21

D

0.26

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The correct Answer is:
To solve the problem step by step, we will use the given percentages and apply the principle of inclusion-exclusion in set theory. ### Step 1: Understand the Information Given We know: - 68% of students favor at least one of the magazines (A, B, or C). - 38% favor magazine A. - 26% favor magazine B. - 36% favor magazine C. - 11% favor more than one magazine. ### Step 2: Set Up the Equations Let: - \( x \) = percentage of students who favor only magazine A. - \( y \) = percentage of students who favor only magazine B. - \( z \) = percentage of students who favor only magazine C. - \( p \) = percentage of students who favor both A and B (but not C). - \( q \) = percentage of students who favor both A and C (but not B). - \( r \) = percentage of students who favor both B and C (but not A). - \( s \) = percentage of students who favor all three magazines A, B, and C. From the problem, we can set up the following equations based on the information provided: 1. \( x + y + z + p + q + r + s = 68 \) (total who favor at least one magazine) 2. \( x + p + q + s = 38 \) (total who favor magazine A) 3. \( y + p + r + s = 26 \) (total who favor magazine B) 4. \( z + q + r + s = 36 \) (total who favor magazine C) 5. \( p + q + r + s = 11 \) (those who favor more than one magazine) ### Step 3: Solve the Equations We can use the fifth equation to express \( p + q + r + s \) in terms of the other variables. We know that \( p + q + r + s = 11 \). Now we can substitute this into the first equation: 1. \( x + y + z + 11 = 68 \) \[ x + y + z = 68 - 11 = 57 \] ### Step 4: Find the Percentage of Students Who Favor More Than One Magazine From the fifth equation, we already know that 11% of students favor more than one magazine. Thus, the percentage of students who favor more than one of the three magazines is: \[ \text{Percentage} = 11\% \] ### Step 5: Conclusion The answer to the question is that **11% of those surveyed favored more than one of the three magazines**.
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ARIHANT SSC-SET THEORY-EXERCISE - 15 (LEVEL -1)
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