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Given log 2 = 0.3010 and log 3= 0.4771. ...

Given log 2 = 0.3010 and log 3= 0.4771. Find the value of log 0.0075

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To find the value of \( \log 0.0075 \), we can follow these steps: ### Step 1: Rewrite the logarithm We start by rewriting \( 0.0075 \) in a more manageable form. We can express \( 0.0075 \) as: \[ 0.0075 = \frac{75}{10000} = \frac{75}{10^4} \] Thus, we have: \[ \log 0.0075 = \log \left( \frac{75}{10^4} \right) \] ### Step 2: Apply the logarithmic property Using the property of logarithms that states \( \log \left( \frac{m}{n} \right) = \log m - \log n \), we can separate the logarithm: \[ \log 0.0075 = \log 75 - \log 10^4 \] ### Step 3: Simplify \( \log 10^4 \) We know that \( \log 10^4 = 4 \log 10 \). Since \( \log 10 = 1 \), we have: \[ \log 10^4 = 4 \] Thus, we can rewrite our expression as: \[ \log 0.0075 = \log 75 - 4 \] ### Step 4: Express \( \log 75 \) Next, we can express \( 75 \) as \( 3 \times 25 \): \[ \log 75 = \log (3 \times 25) = \log 3 + \log 25 \] Since \( 25 = 5^2 \), we can further simplify: \[ \log 25 = \log (5^2) = 2 \log 5 \] So, we have: \[ \log 75 = \log 3 + 2 \log 5 \] ### Step 5: Substitute known values Now we substitute the known values of \( \log 2 \) and \( \log 3 \) into our equation. However, we need to find \( \log 5 \). We can use the relationship: \[ \log 10 = \log (2 \times 5) = \log 2 + \log 5 \] Since \( \log 10 = 1 \), we can rearrange this to find \( \log 5 \): \[ \log 5 = 1 - \log 2 = 1 - 0.3010 = 0.6990 \] ### Step 6: Substitute \( \log 3 \) and \( \log 5 \) Now we substitute \( \log 3 \) and \( \log 5 \) into the equation for \( \log 75 \): \[ \log 75 = \log 3 + 2 \log 5 = 0.4771 + 2 \times 0.6990 \] Calculating \( 2 \times 0.6990 \): \[ 2 \times 0.6990 = 1.3980 \] Thus: \[ \log 75 = 0.4771 + 1.3980 = 1.8751 \] ### Step 7: Final calculation Now we can substitute back into our equation for \( \log 0.0075 \): \[ \log 0.0075 = \log 75 - 4 = 1.8751 - 4 = -2.1249 \] ### Conclusion Therefore, the value of \( \log 0.0075 \) is: \[ \log 0.0075 = -2.1249 \] ---
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ARIHANT SSC-LOGARITHM -EXERCISE LEVEL 2
  1. Given log 2 = 0.3010 and log 3= 0.4771. Find the value of log 0.0075

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  2. Find the sum of 'n' terms of the series. log(2)(x/y) + log(4)(x/y)^(...

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  3. Find the value of log m + logm^(2) + log m^(3) +……. + log m^(n):

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  4. The greatest possible value of n could be if 9^(n)lt10^(8), given tha...

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  5. The set of solution for all x satisfying the equation x^(log 3 x^(2...

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  6. The set of all the solution of the inequality log(2-x) (x-3) ge 1 is :

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  7. If log(3)30 =1/a and log(5) 30 = 1/b then the value of 3 log(30)2 is:

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  8. Number of ways in which 20 different pearls of two colours can be set ...

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  9. The number of solutions of the expression satisfying 4^(x^(2)+2)-9.2^(...

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  10. Six teachers and six students have to sit round a circular table such ...

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  11. The number of different words which can be formed from the letters of ...

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  12. If a denotes the number of permutation of x+2 things taken all at a ti...

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  13. The set S={1,2,3,...,12} is to be partitioned into three sets, A, B, C...

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  14. The number of solutions of the equation log(x//2)x^(2) + 40 log(4x)...

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  15. Ravish writes letters to his five friends and addresses the correspond...

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  16. f:{1,2,3,4,5}→{1,2,3,4,5} that are onto and f(i)≠i, is equal to

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  17. The least value of expression 2 log(10)x - log(x) (1//100) for x gt 1 ...

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  18. The equation x^((3//4) (log(2)x)^(2) + log(2)x - (5//4)) = sqrt(2) has...

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  19. From 6 different novels and 3 different dictionaries, 4 novels and 1 d...

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  20. Find all real values of x satisfying equation: |x-1|^(log x^(2) - 2 ...

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