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The value of ""(216)log(6) 39 is...

The value of `""_(216)log_(6) 39` is

A

117694

B

117649

C

216649

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( 216^{\log_6 39} \), we can follow these steps: ### Step 1: Rewrite 216 in terms of base 6 We know that \( 216 = 6^3 \). Therefore, we can rewrite the expression as: \[ 216^{\log_6 39} = (6^3)^{\log_6 39} \] ### Step 2: Apply the power of a power property Using the property of exponents \( (a^m)^n = a^{m \cdot n} \), we can simplify the expression: \[ (6^3)^{\log_6 39} = 6^{3 \cdot \log_6 39} \] ### Step 3: Use the property of logarithms We can use the property of logarithms that states \( a^{\log_a b} = b \). In our case, we can rewrite \( 3 \cdot \log_6 39 \) as: \[ 6^{3 \cdot \log_6 39} = 39^3 \] ### Step 4: Calculate \( 39^3 \) Now we need to calculate \( 39^3 \): \[ 39^3 = 39 \times 39 \times 39 \] Calculating this gives: \[ 39 \times 39 = 1521 \] Then, \[ 1521 \times 39 = 59319 \] ### Final Answer Thus, the value of \( 216^{\log_6 39} \) is: \[ \boxed{59319} \]
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