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Let A = {1,2,3,4}, B = { 1,5,9,11,15,16}...

Let A = {1,2,3,4}, B = { 1,5,9,11,15,16} and f = {(1,5), (2,9),(3,1),(4,5),(2,11)}. Then ,

A

f is a relation from A to B

B

f is a function from A to B

C

Both (a) and (b)

D

None of these

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The correct Answer is:
To solve the problem, we need to analyze the sets and the relation given. ### Step 1: Identify the Sets and the Relation We have: - Set \( A = \{1, 2, 3, 4\} \) - Set \( B = \{1, 5, 9, 11, 15, 16\} \) - Relation \( f = \{(1, 5), (2, 9), (3, 1), (4, 5), (2, 11)\} \) ### Step 2: Determine if \( f \) is a Relation from \( A \) to \( B \) A relation from set \( A \) to set \( B \) means that every first element (from set \( A \)) in the ordered pairs of \( f \) must be an element of \( A \) and every second element (from set \( B \)) must be an element of \( B \). - Check the first elements of the pairs in \( f \): - \( 1 \) is in \( A \) - \( 2 \) is in \( A \) - \( 3 \) is in \( A \) - \( 4 \) is in \( A \) - \( 2 \) is in \( A \) again Since all first elements are in \( A \), we check the second elements: - Check the second elements of the pairs in \( f \): - \( 5 \) is in \( B \) - \( 9 \) is in \( B \) - \( 1 \) is in \( B \) - \( 5 \) is in \( B \) again - \( 11 \) is in \( B \) Since all second elements are in \( B \), we conclude that \( f \) is indeed a relation from \( A \) to \( B \). ### Step 3: Determine if \( f \) is a Function from \( A \) to \( B \) For \( f \) to be a function from \( A \) to \( B \), each element in \( A \) must map to exactly one element in \( B \). - Check the mappings: - \( 1 \) maps to \( 5 \) - \( 2 \) maps to \( 9 \) and \( 11 \) (two outputs) - \( 3 \) maps to \( 1 \) - \( 4 \) maps to \( 5 \) Since the element \( 2 \) in \( A \) maps to two different elements in \( B \) (both \( 9 \) and \( 11 \)), \( f \) does not satisfy the condition of being a function. ### Conclusion - \( f \) is a relation from \( A \) to \( B \). - \( f \) is not a function from \( A \) to \( B \). Thus, the correct option is that \( f \) is a relation from \( A \) to \( B \) but not a function. ### Final Answer - \( f \) is a relation from \( A \) to \( B \) (Option A).
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DISHA PUBLICATION-RELATIONS AND FUNCTIONS -EXERCISE - 1
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  2. the value of the function f(x)=(x^2-3x+2)/(x^2+x-6) lies in the inter...

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  3. Let A = {1,2,3,4}, B = { 1,5,9,11,15,16} and f = {(1,5), (2,9),(3,1),(...

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  4. Which of the following relation is a function ?

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  7. There are three relations R(1) , R(2) and R(3) such that R(1) = {(2,...

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  8. The domain of definiton of the function f(x)=(1)/(sqrt(x^(12)-x^(9)+x^...

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  9. The domain and range of the real function f defined by f(x)=(4-x)/(x-4...

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  11. The domain of the function f(x) = (x^(2) + 3x+ 5)/(x^(2) -5x + 4) is

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  12. The domain of the function f given by f(x) = (x^(2)+ 2x+ 1)/(x^(2) - 5...

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  13. Find the domain of f(x)=sqrt((log)(0. 4)((x-1)/(x+5)))

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  14. If f(x)=(x)/(x-1), then what is (f(a))/(f(a+1)) equal to?

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  15. If phi(x)=a^x, then [phi(p)]^3 is equal to:

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  16. The function f(x)=log(x+sqrt(x^(1)+1)) is

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  17. The domain of the function f(x) = (|x+3|)/(x + 3) is

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  18. If 3 f(x) - f((1)/(x) ) = log x^(4) , then f(e^(-x)) is

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  19. If f(x) = x^(3) - (1)/(x^(3)) then f (x) + f((1)/(x)) is equal to

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  20. Is g={(1,1),(2,3),(3,5,),(4,7)} a function? If this is described by th...

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