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Which of the following relation is a fun...

Which of the following relation is a function ?

A

{(a,b) (b,e)(c,e) (b,x)}

B

{(a,d)(a,b)(b,e)(a,b)}

C

{(a,d)(b,e)(c,d)(e,x)}

D

{(a,b)(b,m)(b,y)(d,x)}

Text Solution

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The correct Answer is:
To determine which of the given relations is a function, we need to analyze each option based on the definition of a function. A relation is a function if: 1. Every element in set A (domain) is associated with exactly one element in set B (codomain). 2. No two different elements in set A map to the same element in set B. Let's analyze the options step by step: ### Step 1: Analyze Option A - **Relation**: {(A, B), (B, E), (C, E), (B, X)} - **Elements in Set A**: {A, B, C} - **Elements in Set B**: {B, E, X} In this relation: - A maps to B - B maps to E - C maps to E - B maps to X Here, B is mapped to both E and X, which violates the rule that each element in A must map to a unique element in B. Therefore, **Option A is not a function**. ### Step 2: Analyze Option B - **Relation**: {(A, D), (A, B), (B, E)} - **Elements in Set A**: {A, B} - **Elements in Set B**: {D, B, E} In this relation: - A maps to D - A maps to B - B maps to E Again, A is mapped to both D and B, which violates the uniqueness condition. Therefore, **Option B is not a function**. ### Step 3: Analyze Option C - **Relation**: {(A, D), (B, E), (C, D), (E, X)} - **Elements in Set A**: {A, B, C, E} - **Elements in Set B**: {D, E, X} In this relation: - A maps to D - B maps to E - C maps to D - E maps to X Here, A and C both map to D, but since they are different elements in A, it does not violate the uniqueness condition. Each element in A is mapped to an element in B, and no two elements in A map to the same element in B. Therefore, **Option C is a function**. ### Step 4: Analyze Option D - **Relation**: {(A, B), (B, M), (B, N), (D, X)} - **Elements in Set A**: {A, B, D} - **Elements in Set B**: {B, M, N, X} In this relation: - A maps to B - B maps to M - B maps to N - D maps to X Here, B is mapped to both M and N, which violates the uniqueness condition. Therefore, **Option D is not a function**. ### Conclusion The only relation that satisfies the conditions of being a function is **Option C**.
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