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A relation R is defined in the set Z of ...

A relation R is defined in the set Z of integers as follows (x, y ) `in` R iff `x^(2) + y^(2)` = 9 . Which of the following is false ?

A

R = { (0,3), (0,-3), (3,0), (-3,0)}

B

Domain of R = { - 3, 0, 3}

C

Range of R = {-3, 0, 3}

D

None of these

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The correct Answer is:
To solve the problem, we need to analyze the relation \( R \) defined on the set of integers \( \mathbb{Z} \) such that \( (x, y) \in R \) if and only if \( x^2 + y^2 = 9 \). We will find the ordered pairs that satisfy this equation and then determine the domain and range of the relation. ### Step-by-Step Solution: 1. **Understanding the Equation**: We start with the equation \( x^2 + y^2 = 9 \). This represents a circle with a radius of 3 centered at the origin in the coordinate system. 2. **Finding Integer Solutions**: We need to find all integer pairs \( (x, y) \) that satisfy this equation. We can do this by considering possible values for \( x \) and calculating \( y \). - If \( x = 0 \): \[ 0^2 + y^2 = 9 \implies y^2 = 9 \implies y = 3 \text{ or } y = -3 \implies (0, 3), (0, -3) \] - If \( x = 1 \): \[ 1^2 + y^2 = 9 \implies 1 + y^2 = 9 \implies y^2 = 8 \text{ (not an integer)} \] - If \( x = 2 \): \[ 2^2 + y^2 = 9 \implies 4 + y^2 = 9 \implies y^2 = 5 \text{ (not an integer)} \] - If \( x = 3 \): \[ 3^2 + y^2 = 9 \implies 9 + y^2 = 9 \implies y^2 = 0 \implies y = 0 \implies (3, 0) \] - If \( x = -1 \): \[ (-1)^2 + y^2 = 9 \implies 1 + y^2 = 9 \implies y^2 = 8 \text{ (not an integer)} \] - If \( x = -2 \): \[ (-2)^2 + y^2 = 9 \implies 4 + y^2 = 9 \implies y^2 = 5 \text{ (not an integer)} \] - If \( x = -3 \): \[ (-3)^2 + y^2 = 9 \implies 9 + y^2 = 9 \implies y^2 = 0 \implies y = 0 \implies (-3, 0) \] 3. **Compiling the Ordered Pairs**: From the calculations above, the integer pairs that satisfy \( x^2 + y^2 = 9 \) are: - \( (0, 3) \) - \( (0, -3) \) - \( (3, 0) \) - \( (-3, 0) \) Thus, the relation \( R \) can be expressed as: \[ R = \{ (0, 3), (0, -3), (3, 0), (-3, 0) \} \] 4. **Finding the Domain and Range**: - **Domain**: The set of all first elements (x-coordinates) in the ordered pairs: \[ \text{Domain} = \{ 0, 3, -3 \} \] - **Range**: The set of all second elements (y-coordinates) in the ordered pairs: \[ \text{Range} = \{ 3, -3, 0 \} \] 5. **Identifying the False Statement**: We need to determine which of the provided options is false. Since the domain and range have been correctly identified, we can conclude that options A, B, and C are true, and thus the correct answer is option D, which states that none of the statements is false. ### Conclusion: The final answer is option D: None of these statements is false.
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DISHA PUBLICATION-RELATIONS AND FUNCTIONS -EXERCISE - 2
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  4. Let f (x) = [x], where [x] denotes the greatest integer less than or e...

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  9. the value of the function f(x)=(x^2-3x+2)/(x^2+x-6) lies in the inter...

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  10. The domain of f (x) = log (|x - 2 | - 2 | - 1) is

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  11. If f:R to R satisfies f(x+y)=f(x)+f(y), for all x, y in R and f(1)=7,...

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  12. Find the domain of the following functions: f(x)=sqrt((2/(x^2-x+1)-1/(...

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  13. Which of the following functions is even,

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  14. If f(1) = 1 and f(n + 1) = 2 f(n) + 1, if n ge 1, then f(n) is.

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  15. The range of the function f(x)= (x^2-x+1)/(x^2+x+1) where x in R, is

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  17. The domain of the function f (x) = 3sqrt((x)/(1 - |x|))

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  19. If f is any function, then (1)/(2) [ f (x) + f(-x) ] is always

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  20. The function f satisfies the functional equation 3f(x)+2f((x+59)/(x1))...

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