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The locus of the foot of prependicular d...

The locus of the foot of prependicular drawn from the center of the ellipse `x^(2)+3y^(2)=6` on any tangent to it is

A

`(x^(2)+y^(2))^(2)=6x^(2)+2y^(2)`

B

`(x^(2)+y^(2))^(2)=6x^(2)-2y^(2)`

C

`(x^(2)-y^(2))^(2)=6x^(2)+2y^(2)`

D

`(x^(2)-y^(2))^(2)=6x^(2)-2y^(2)`

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The correct Answer is:
A
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DISHA PUBLICATION-CONIC SECTIONS-Exercise-2 : Concept Applicator
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