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If two circles S1=x^2+y^2+2gx+2fy+c=0 an...

If two circles `S_1=x^2+y^2+2gx+2fy+c=0` and `S_2=x^2+y^2+2g'x+2f'y+c'=0` to be cut orthogonally then show that :`2gg'+2ff'=c+c'`

A

`2g_(1)g_(2)+2f_(1)f_(2)=c_(1)+c_(2)`

B

`2g_(1)g_(2)-2f_(1)f_(2)=c_(1)+c_(2)`

C

`2g_(1)g_(2)+2f_(1)f_(2)=c_(1)-c_(2)`

D

`2g_(1)g_(2)-2f_(1)f_(2)=c_(1)-c_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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