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If the circles x^2 + y^2 + 2gx + 2fy + c...

If the circles `x^2 + y^2 + 2gx + 2fy + c = 0` bisects `x^2+y^2+2g'x+2f'y + c' = 0` then the length of the common chord of these two circles is -

A

2g'(g-g')+2f'(f-f')=c-c'

B

2g(g-g')+2f(f-f')=c-c'

C

g'(g-g')+f'(f-f')=c-c'

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
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