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Find the point on the parabolas x^2=2...

Find the point on the parabolas `x^2=2y` which is closest to the point `(0,\ 5)` .

A

`(pm2sqrt2,4)`

B

`(pm2, 2)`

C

`(pm3,9//2)`

D

`(pmsqrt2,1)`

Text Solution

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The correct Answer is:
A
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