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The normal at the point (bt1^2, 2bt1) on...

The normal at the point `(bt_1^2, 2bt_1)` on the parabola `y^2 = 4bx` meets the parabola again in the point `(bt_2 ^2, 2bt_2,)` then

A

`t_(2)=t_(1)+2/t_(1)`

B

`t_(2)=-t_(1)-2/t_(1)`

C

`t_(2)=-t_(1)+2/t_(1)`

D

`t_(2)=t_(1)-2/t_(1)`

Text Solution

Verified by Experts

The correct Answer is:
B
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