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If e1 is the eccentricity of the ellipse...

If `e_1` is the eccentricity of the ellipse `x^2/16+y^2/25=1 and e_2` is the eccentricity of the hyperbola passing through the foci of the ellipse and `e_1 e_2=1`, then equation of the hyperbola is

A

`x^(2)/9-y^(2)/16=1`

B

`x^(2)/9-y^(2)/16=-1`

C

`x^(2)/9-y^(2)/25=-1`

D

`x^(2)/9-y^(2)/36=1`

Text Solution

Verified by Experts

The correct Answer is:
B
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