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If a!=0 and the line 2bx+3cy+4d=0 passes...

If `a!=0` and the line `2bx+3cy+4d=0` passes through the points of intersection of the parabola `y^2 = 4ax` and `x^2 = 4ay`, then

A

`d^(2)+(3b-2c)^(2)=0`

B

`d^(2)+(3b+2c)^(2)=0`

C

`d^(2)+(2b+3c)^(2)=0`

D

`d^(2)+(2b+3c)^(2)=0`

Text Solution

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The correct Answer is:
D
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