Home
Class 12
MATHS
3 friends A, B and C play the game "Pahl...

3 friends A, B and C play the game "Pahle Hum Pahle Tum" in which they throw a die one after the other and the one who will get a composite number `1^(st)` will be announced as winner, If A started the game followed by B and then C then what is the ratio of their winning probabilities?

A

`9:6:4`

B

`8:6:5`

C

`10:5:4`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • PROBABILITY -2

    DISHA PUBLICATION|Exercise EXERCISE - 1 : CONCEPT BUILDER|60 Videos

  • PRINCIPLE OF MATHEMATICAL INDUCTION

    DISHA PUBLICATION|Exercise Exercise-2 Concept Applicator|20 Videos

  • PROBABILITY-1

    DISHA PUBLICATION|Exercise EXERCISE-1 : CONCEPT BUILDER|180 Videos

Similar Questions

Explore conceptually related problems

In a hockey match, both teams A and B scored same number of goals upto the end of the game, so to decide the winner, the referee asked both the captains to throw a die alternately and decided that the team whose captain gets a six first, will be declared the winner. If the captain of team A was asked to start, then find their respective probabilities of winning the match and state whether the decision of the referee was fair or not.

A, B and C in turn throw a die and one who gets a 6 first, wins the game. A takes the first chance followed by B and C, and the process is repeated till one them who gets a 6, wins the game. Find the probabilities of each for winning the game.

Knowledge Check

  • Raj and Sanchita are playing game in which they throw two dice alternately till one of them gets 9. Which one of the following could be the probability that Sanchita win the game?

    A
    `7/15 or 8/15`
    B
    `6/11 or 5/11`
    C
    `8/17 or 9/17`
    D
    None of these

  • A, B, C in order roll a dice on the condition that one who gets a six, first wins then which of the following are true

    A
    A chances `36/91`
    B
    B chances `5/6.(36)/(91)`
    C
    C chances `(5/6)^(2)(36)/(91)`
    D
    All three has same chances

  • A,B,C in other toss a coin. The first one to throw a head wins. Assuming the game continues indefinite their respective chances of winning the game are

    A
    `4/7,2/7,1/7`
    B
    `1/7,4/7,2/7`
    C
    `2/7,4/7,1/7`
    D
    none

    • Similar Questions

    Explore conceptually related problems

    A and B alternately throw with a pair of dice. Who gets a sum of 7 points 1 th will win the game.If A starts the game,the probability of his winning is

    A and B toss a coin alternately till one of them gets a head and wins the game. If A starts the game, find the probability that B will win the game.

    A,B and C toss a coin one after another. Who ever gets head list will win the game.If A starts the game the probability of Al's winning is

    A and B throw a dice alternately til any one gets a 6 on the and win the game. If A begins the game find the probabilities of winning the game.

    A, B and C play a game and chances of their winning it in an attempt are (2)/(3),(1)/(2) and (1)/(4) respectively. A has the first chance, followed by B and then by C. The cycle is repeated till one of them wins the game. Find their respective chances of winning the game.

    Home
    Profile