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Let vecalpha = 3hati + hatj and beta= 2h...

Let `vecalpha = 3hati + hatj` and `beta= 2hati - hatj + 3hatk`. If `vecbeta = vecbeta_(1) - vecbeta_(2)`, where `vecbeta_(1)` is parallel to `vecalpha` and `vecbeta_(2)` is perpendicular to `vecalpha`, then `vecbeta_(1) xx vecbeta_(2)` is equal to:

A

`-3hati+9hatj+ 5hatk`

B

`3hati-9hatj-5hatk`

C

`(1)/(2)(-3hati+9hatj+ 5hatk)`

D

`(1)/(2)(3hati-9hatj+ 5hatk)`

Text Solution

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The correct Answer is:
C
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