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If `[{:(1, 1), (0,1):}]*[{:(1, 2), (0,1):}]*[{:(1, 3), (0,1):}]cdotcdotcdot[{:(1, n-1), (0,1):}] = [{:(1, 78), (0,1):}]`, then the inverse of `[{:(1, n), (0,1):}]` is

A

`[[1,0],[12,1]]`

B

`[[1,-13],[0,1]]`

C

`[[1,-12],[0,1]]`

D

`[[1,0],[13,1]]`

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The correct Answer is:
B
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