A body of mass 4 kg moving on a horizontal surface with an initial velocity of `6ms^(-1)` comes to rest after 3 seconds. If one wants to keep the body moving on the same surface with the velocity of `6ms^(-1)` the force required is

Options

A. zero
B. 4N
C. 8N
D. 16N

Answer

C

Explanation

Acceleration of `a=(v-u)/(t)=(0-6)/(3)=-2ms^(-2)`
Force `=mxxa=4xx8N`