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An open topped rail road car of mass M h...

An open topped rail road car of mass M has an initial velocity `v_(0)` along a straight horizontal frictionless track. It suddenly starts raising at timet = 0. The rain drops fall vertically with velocity u and add a mass m kg/sec of water. The velocity of car after t second will be (assuming that it is not completely filled with water)

A

`v_(0)+m(u)/(M)`

B

`(Mv_(0))/(M+mt)`

C

`(Mv_(0)+ut)/(M+ut)`

D

`v_(0)+(m""ut)/(M+ut)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will apply the principle of conservation of momentum. Here are the steps to derive the final velocity of the railroad car after time \( t \): ### Step 1: Understand the system - The railroad car has an initial mass \( M \) and an initial velocity \( v_0 \). - It starts raining at \( t = 0 \), adding mass to the car at a rate of \( m \) kg/sec. - The raindrops fall vertically with velocity \( u \), which does not affect the horizontal motion of the car. ### Step 2: Identify the initial momentum - The initial momentum \( p_i \) of the system (car) is given by: \[ p_i = M \cdot v_0 \] ### Step 3: Determine the mass after time \( t \) - After \( t \) seconds, the mass of the car will increase due to the rain. The additional mass added is: \[ \text{Added mass} = m \cdot t \] - Therefore, the total mass of the car after \( t \) seconds becomes: \[ M_f = M + m \cdot t \] ### Step 4: Apply conservation of momentum - Since there are no external horizontal forces acting on the system, the horizontal momentum is conserved. Thus, the final momentum \( p_f \) of the system is: \[ p_f = M_f \cdot v_f \] where \( v_f \) is the final velocity of the car after time \( t \). ### Step 5: Set initial momentum equal to final momentum - According to the conservation of momentum: \[ p_i = p_f \] Substituting the expressions for momentum: \[ M \cdot v_0 = (M + m \cdot t) \cdot v_f \] ### Step 6: Solve for the final velocity \( v_f \) - Rearranging the equation to solve for \( v_f \): \[ v_f = \frac{M \cdot v_0}{M + m \cdot t} \] ### Conclusion - The final velocity of the railroad car after time \( t \) is given by: \[ v_f = \frac{M \cdot v_0}{M + m \cdot t} \]

To solve the problem, we will apply the principle of conservation of momentum. Here are the steps to derive the final velocity of the railroad car after time \( t \): ### Step 1: Understand the system - The railroad car has an initial mass \( M \) and an initial velocity \( v_0 \). - It starts raining at \( t = 0 \), adding mass to the car at a rate of \( m \) kg/sec. - The raindrops fall vertically with velocity \( u \), which does not affect the horizontal motion of the car. ### Step 2: Identify the initial momentum ...
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