A 0.1 kg block suspended from a massless string is moved first vertically up with an acceleration of `5ms^(–2)` and then moved vertically down with an acceleration of `5ms^(–2)`. If `T_(1)` and `T_(2)` are the respective tensions in the two cases, then

Options

A. `T_(2)gtT_(1)`
B. `T_(1)-T_(2)=1N,` if `g=10ms^(-2)`
C. `T_(1)-T_(2)=1kgf`
D. `T_(1)-T_(2)=9.8N`, if `g=9.8ms^(-2)`

Answer

B

Explanation

`T_(1)=m(g+a)=0.1(10+5)=1.5`
`T_(2)=m(g-a)=0.1(10-5)=0.5N`
`rArr T_(1)-T_(2)=(1.5-0.5)N=1N`