A motor cyclist moving with a velocity of 72 km/hour on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 meters . The acceleration due to gravity is `10m//sec^(2)`. In order to avoid skidding, he must not bend with respect to the vertical plane by an angle greater than

Options

A. `tan=tan^(-1)6`
B. `theta=tan^(-1)2`
C. `theta=tan^(-1)25.92`
D. `theta=tan^(-1)4`

Answer

B

Explanation

`tan theta=(v^(2))/(rg)=((72xx1000)/(3600))^(2)//20xx10=2`