Number of moles of `K_2Cr_2O_7` reduced by one mole of `Sn^(2+)` ion is

Options

A. 1/3
B. 3
C. 1/6
D. 6

Answer

A

Explanation

(a) `(Cr_2O_(7)^(2-) + I4H^(+) + 6e^(-) rarr 2Cr^(3+) + 7H_2O)1/3 Sn^(2+) - 2e^(-) rarr Sn^(4+)` on adding `1/3 Cr_2O_(7)^(2-) + 14/3 H^(+) Sn^(+2) rarr 2/3Cr^(+3) + 7/3H_2O + Sn^(4+)`