Equivalent mass of oxidizing agent in the reaction,
`SO_(2)+2H_(2)S rarr 3S+2H_(2)O` is

Options

A. 32
B. 64
C. 16
D. 8

Answer

C

Explanation

© In the reaction `SO_2 + 2H_2S rarr 3S + 2H_2O` acts as an oxidising agent as Reduction `S overset(+4)(O)_2 rarr overset(0)(S)`
To balance oxidation number, add `4e^(-)` to L.H.S. `SO_2 +4e^(-) rarr overset(0)S` Therefore, this reaction is a four electron change and Equivalent weight of `SO_2`
-1/4 x Molecular weight = 1/4 x 64 = 16