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The oxidation states of the most electro...

The oxidation states of the most electronegative element in the products of the reaction between `BaO_2` with dilute `H_2SO_4` are

A

0 and -1

B

-1 and -2

C

-2 and 0

D

-2 and-1

Text Solution

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The correct Answer is:
B

(b) `BaO_2, + H_2SO_4 rarr BaSO_4, + H_2O2` Oxygen is the most elcctronegative element in the reaction and has the oxidation states of -1 ( in `H_2O_2`,) and -2 (in `BaSO_4`,). In `H_2O_2`, peroxo ion is present.
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