One mole of an unsaturated hydrocarbon on ozonolysis gives one mole each of `CH_(3)CHO,HCHO, and OCH-CHO`. The hydrocarbon is

Options

A. `CH_(3) - CH=C C(CH_(3))-CH_(3)`
B. `CH_(2) = CH - CH_(2)-CH =CH_(2)`
C. `CH_(2)=CH-C(CH_(3))=CH -CH_(3)`
D. `(CH_(3))_(2)C=CH-CH_(3)`

Answer

c

Explanation

`CH_(2)=CH-C(CH_(3))=CH - CH_(3) overset(O_(3)) underset (Zn//H_(2)O) to`
`CH_(2)O + O = CH - underset (O) underset("||")C - CH_(3)+CH_(3)CHO`
For solving such question remove thee double bonds and join the carbons to oxygen by double bonds .