An organic compound 'X' - (molecular formula `C_(6)H_(7)O_(2)`N) has six atoms in a ring system two double bonds and a nitro group as substituent , 'X' is

Options

A. hetercyclic
B. homocyclic and aromatic
C. aromatic but not homocyclic
D. homocyclic but not aromatic

Answer

To solve the problem regarding the organic compound 'X' with the molecular formula C6H7O2N, we will follow these steps:

### Step 1: Analyze the Molecular Formula
The molecular formula C6H7O2N indicates that the compound contains:
- 6 Carbon (C) atoms
- 7 Hydrogen (H) atoms
- 2 Oxygen (O) atoms
- 1 Nitrogen (N) atom

### Step 2: Identify the Structure
Given that there are six atoms in a ring system and two double bonds, we can deduce that the compound is likely to be a cyclic compound. The presence of a nitro group (NO2) as a substituent suggests that it is attached to one of the carbon atoms in the ring.

### Step 3: Determine the Type of Ring
Since the compound has only carbon atoms in the ring and a nitrogen atom as a substituent, it is classified as a homocyclic compound. The presence of two double bonds indicates that the compound may be a conjugated system.

### Step 4: Check for Aromaticity
To determine if the compound is aromatic, we need to check:
- All atoms must be in the same plane (planarity).
- The compound must follow Huckel's rule (4n + 2 π electrons).

However, since we have sp3 hybridized carbon atoms, the compound is not planar, and thus it does not fulfill the criteria for aromaticity. Therefore, it is not aromatic.

### Step 5: Conclude the Structure
Based on the analysis, we can conclude that the compound 'X' is a homocyclic compound with a nitro group and two double bonds. The correct structure for 'X' can be represented as a cyclic compound with the nitro group attached to one of the carbon atoms in the ring.

### Final Answer
The organic compound 'X' is a homocyclic compound with the formula C6H7O2N, featuring a nitro group and two double bonds, but it is not aromatic.

---