Consider the following sequence of reactions
`CH_(3) CH = CH_(2) overset (Cl_(2)) underset (700 K) to A overset (Na_(2)CO_(3)) underset ( 420 K , 12atm) to B overset ((i) HOCl) underset ((ii) NaOh) to C `
Compound 'C' is

Options

A.
B. `overset (CH_(3)CHCOONa) overset (|) (OH) `
C. `HOCH_(2) - CH = CH_(2)`
D. `overset (CH_(3)CHCOCl) overset (|) (OH)`

Answer

To solve the problem step by step, we will analyze each reaction in the sequence provided.

### Step 1: Reaction of CH₃CH=CH₂ with Cl₂
- **Starting Compound:** CH₃CH=CH₂ (Propene)
- **Reagent:** Cl₂ (Chlorine gas) at 700 K
- **Reaction Type:** Electrophilic addition
- **Mechanism:** The double bond (π bond) in propene attacks the Cl₂ molecule, leading to the formation of a cyclic chloronium ion. The Cl⁻ ion then attacks the more substituted carbon, resulting in a vicinal dichloride.

**Product A:**
- The product formed is 1,2-dichloropropane (CH₃CHClCH₂Cl).

### Step 2: Reaction of A with Na₂CO₃
- **Starting Compound:** A (1,2-dichloropropane)
- **Reagent:** Na₂CO₃ (Sodium carbonate) at 420 K and 12 atm
- **Reaction Type:** Elimination reaction
- **Mechanism:** The base (Na₂CO₃) abstracts a proton from the less hindered side (the CH₂ group), resulting in the elimination of one of the Cl atoms and forming a double bond.

**Product B:**
- The product formed is propene (CH₃CH=CH₂) again.

### Step 3: Reaction of B with HOCl
- **Starting Compound:** B (Propene)
- **Reagent:** HOCl (Hypochlorous acid)
- **Reaction Type:** Electrophilic addition
- **Mechanism:** The π bond in propene attacks the electrophilic Cl in HOCl, leading to the formation of a chlorohydrin.

**Product C:**
- The product formed is 1-chloro-2-propanol (CH₃CH(Cl)CH₂OH).

### Step 4: Reaction of C with NaOH
- **Starting Compound:** C (1-chloro-2-propanol)
- **Reagent:** NaOH (Sodium hydroxide)
- **Reaction Type:** Nucleophilic substitution
- **Mechanism:** The hydroxide ion (OH⁻) acts as a nucleophile and attacks the carbon bonded to the chlorine, leading to the substitution of the Cl atom with OH.

**Final Product C:**
- The final product is 2-propanol (isopropanol, CH₃CHOHCH₃).

### Conclusion
The compound 'C' is **2-propanol (isopropanol)**.

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