In a face centred cubic lattice, atom `A` occupies the corner positions and atom `B` occupies the face centred positions. If one atom of `B` is missin from one of the face centred points,, the formula of the compound is `:`

Options

A. `AB_2`
B. `A_5B_2`
C. `A_2B_3`
D. `A_2B_5`

Answer

D

Explanation

Number of atoms ` A = 1/8 xx 8 = 1`
Number of atoms B ` = 1/2 xx 5 = 5/2`
(Since atom B is missing from one of the face centered point)
Formula of ionic compound= `AB_(5//2) = A_2B_5`