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Each edge of a cubic unit cell is 400pm...

Each edge of a cubic unit cell is 400pm long. If atomic mass of the elements is 120 and its desity is `6.25g//cm^(2)`, the crystal lattice is: `(use N_(A)=6 xx 10^(23))`

A

Primitive

B

Body centered

C

Face centered

D

End centered

Text Solution

Verified by Experts

The correct Answer is:
B
`d = (zM)/(N_A a^3) rArr 6.25`
`= (z xx 120)/(6.02 xx 10^23 xx (4 xx 10^(-8) )^3) = 2`
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