The non- stoichiometric compound `Fe_(0.94)O` is formed when `x%` of `Fe^(2+)` ions are replaced by as many `2//3 Fe^(3+)` ions The value of x is:

Options

A. 18
B. 12
C. 15
D. 6

Answer

A

Explanation

The number of `Fe^(3+)` ions replacing x `Fe^(2+)` ions `= (2x)/(3)`
vacancies of cation `x - (2x)/(3) = x // 3`
but `x//3 = 1 - 0.94 = 0.06 , x = 0.06 xx 3 = 0.18 = 18%`