By X-ray diffraction it is found tht nickel `("at mass"=59g "mol"^(-1))`, crystakkuzes with ccp. The edge length of the unit cell is `3.5 Å`. If density of Ni crystal is `9.0g//cm^(3)`, then value of Avogadro's number from the data is:

Options

A. `6.05 xx 10^23`
B. `6.11 xx 10^23`
C. `6.02 xx10^23`
D. `6.023 xx 10^23`

Answer

B

Explanation

`d = (zM_w)/(N_A a^3)`
`Z = 4, a = 3.5 xx 10^(-8) cm , M_w = 59`