Which one of the following exhibits the large number of oxidation states ?

Options

A. `Ti(22)`
B. `V(23)`
C. `Cr(24)`
D. `Mn(25)`

Explanation

To determine which element exhibits the largest number of oxidation states among titanium, vanadium, chromium, and manganese, we will analyze the electronic configurations and the possible oxidation states for each element.

### Step-by-Step Solution:

1. **Identify the Elements and Their Atomic Numbers:**
- Titanium (Ti): Atomic number 22
- Vanadium (V): Atomic number 23
- Chromium (Cr): Atomic number 24
- Manganese (Mn): Atomic number 25

2. **Write the Electronic Configurations:**
- Titanium: [Ar] 3d² 4s²
- Vanadium: [Ar] 3d³ 4s²
- Chromium: [Ar] 3d⁵ 4s¹
- Manganese: [Ar] 3d⁵ 4s²

3. **Determine the Number of Unpaired Electrons:**
- Titanium: 2 unpaired electrons (3d²)
- Vanadium: 3 unpaired electrons (3d³)
- Chromium: 6 unpaired electrons (3d⁵ 4s¹)
- Manganese: 5 unpaired electrons (3d⁵ 4s²)

4. **Identify Possible Oxidation States:**
- **Titanium:** Common oxidation states are +2, +3, +4 (maximum +4).
- **Vanadium:** Common oxidation states are +2, +3, +4, +5 (maximum +5).
- **Chromium:** Common oxidation states are +2, +3, +6 (maximum +6).
- **Manganese:** Common oxidation states are +2, +3, +4, +5, +6, +7 (maximum +7).

5. **Compare the Maximum Oxidation States:**
- Titanium: +4
- Vanadium: +5
- Chromium: +6
- Manganese: +7

6. **Conclusion:**
- Manganese exhibits the largest number of oxidation states, which is +2 to +7.

### Final Answer:
Manganese (Mn) exhibits the largest number of oxidation states.

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