Chloro compound of vanadium has only spin magnetic moment of 1.73 BM. This vanadium chloride has the formula :- (at no. of V=23)

Options

A. `VCl_(2)`
B. `VCl_(4)`
C. `VCl_(3)`
D. `VCl_(5)`

Answer

A

Explanation

`mu = sqrt(n(+2))`
`1.73= sqrt(n(n+2))`
On calculating the value of n we find n=1
No. of unpaired electros =1
hence is configuration will be
`V(23) = [ Ar]3d^2 As^2`
`V^(4+) = [Ar]3d^14s^0`
`therefore` Its chloride has the fornula `VCl_4`