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When an aqueous solution of copper (II) ...

When an aqueous solution of copper (II) sulphate is saturated with ammonia, the blue compound crystallises on evaporation. The formula of this blue compound is:

A

`[Cu(NH_3)SO_(4).H_(2)O` (square planar)

B

`[Cu(NH_(3))_(4)]SO_(4)`(Tetrahedral)

C

`[Cu(NH_2)_6 ] SO_(4)`(Octahedral)

D

`[Cu(SO_(4))(NH_3)_5]` (Octahedral)

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The correct Answer is:
To determine the formula of the blue compound that crystallizes when an aqueous solution of copper (II) sulfate is saturated with ammonia, we can follow these steps: ### Step 1: Understand the Reaction When copper (II) sulfate (CuSO4) is mixed with ammonia (NH3), a complex ion is formed. The ammonia acts as a ligand and coordinates with the copper ion. **Hint:** Remember that ligands are molecules or ions that can donate a pair of electrons to a central metal atom to form a coordination complex. ### Step 2: Identify the Copper Ion In the solution, copper exists in the +2 oxidation state (Cu²⁺). This is important because it determines how many ligands can coordinate with the copper ion. **Hint:** The oxidation state of the metal ion is crucial for understanding its coordination chemistry. ### Step 3: Determine the Coordination Number Copper (II) typically forms complexes with a coordination number of 4 or 6. In this case, with ammonia as a ligand, it forms a square planar complex, which is common for d⁹ metal ions like Cu²⁺. **Hint:** The geometry of the complex can help you predict the coordination number. ### Step 4: Write the Formula of the Complex The ammonia ligands coordinate with the copper ion. Since there are four ammonia molecules coordinating with one copper ion, the formula for the complex ion will include Cu and NH3. Additionally, the sulfate ion (SO4²⁻) is present in the compound. **Hint:** Pay attention to the number of ligands and the counter ions in the final formula. ### Step 5: Include Water of Crystallization When the complex crystallizes, it often includes water molecules as part of the crystal structure. In this case, we have two water molecules (2H2O) associated with the complex. **Hint:** Water of crystallization is common in hydrated salts and should be included in the final formula. ### Step 6: Combine All Components Putting it all together, the formula for the blue compound formed is Cu(NH3)4SO4·2H2O. **Hint:** Make sure to check the final formula for correct stoichiometry and the presence of water of crystallization. ### Final Answer The formula of the blue compound is **Cu(NH3)4SO4·2H2O**.
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DISHA PUBLICATION-THE D- AND F- BLOCK ELEMENTS -EXERCISE - 1 CONCEPT BUILDER (TOPIC 2 : COMPOUNDS OF TRANSITION METALS)
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  9. What would happen when a solution of potassium chromate is treated wit...

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  10. The oxidation state of chromium in the final product formed by the rea...

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  12. KMnO(4) (acidic / alkaline ) is not decolurised by

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  13. Acidified K(2)Cr(2)O(7) solution turns green when NasO(3) is added to ...

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  14. KMnO4 can be prepared fromK2MnO4 as per the reaction: The reaction ...

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  15. The pair of compounds that can exist together is:

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  16. In acidic medium, H(2)O(2) changes Cr(2)O(7)^(-2) to CrO(5) which has ...

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  17. The reaction of aqueous KMnO(4) with H(2)O(2) i acidic conditions give...

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  19. Assuming complete ionization , same moles of which of the following co...

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  20. Which one of the following statements is correct when SO(2) is passed ...

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