The major product formed when 1, 1, 1-trichloro-propane is treated with aqueous potassium hydroxide is:

Options

A. Propyne
B. 1-Propanol
C. 2-Propano
D. Propionic acid

Explanation

To determine the major product formed when 1,1,1-trichloropropane is treated with aqueous potassium hydroxide, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of 1,1,1-Trichloropropane:**
- Propane has three carbon atoms. The structure of 1,1,1-trichloropropane can be drawn as:
```
Cl
|
Cl-C-CH2-CH3
|
Cl
```
- This shows that the central carbon (C) is bonded to three chlorine atoms (Cl) and one hydrogen atom (H).

2. **Understand the Reaction with Aqueous Potassium Hydroxide (KOH):**
- Aqueous KOH dissociates into K⁺ and OH⁻ ions. The OH⁻ ion acts as a nucleophile in this reaction.

3. **Nucleophilic Attack:**
- The OH⁻ ion will attack the electrophilic carbon atom that is bonded to the chlorine atoms. The carbon is electrophilic because the chlorine atoms are electronegative and withdraw electron density, making the carbon partially positive.

4. **Formation of Alcohols:**
- The nucleophilic attack by OH⁻ will lead to the substitution of one chlorine atom with a hydroxyl group (OH). The reaction can be represented as:
```
Cl-C(OH)-CH2-CH3 + Cl
```
- This process can continue as the remaining chlorine atoms are also good leaving groups.

5. **Formation of Propionic Acid:**
- As the reaction proceeds, two more chlorine atoms can be replaced by hydroxyl groups. However, since we cannot have three hydroxyl groups on the same carbon, dehydration occurs. Water (H₂O) is eliminated, leading to the formation of a carbonyl group (C=O).
- The final product after the elimination of water will be propionic acid (C₂H₅COOH):
```
CH3-CH2-C(=O)-OH
```

6. **Conclusion:**
- The major product formed when 1,1,1-trichloropropane is treated with aqueous potassium hydroxide is **propionic acid** (C₂H₅COOH).

### Final Answer:
The major product formed is **propionic acid** (C₂H₅COOH).