Allyl phenyl ether can be prepared by heating:

Options

A. `C_(6)H_(5)Br+CH_(2)=CH-CH_(2)-ON a`
B. `CH_(2)=CH-CH_(2)-Br+C_(6)H_(5)ON a`
C. `C_(6)H_(5)-CH=CH-Br+CH_(3)-ON a`
D. `CH_(2)=CH-Br+C_(6)H_(5)-CH_(2)-ON a`

Explanation

To prepare allyl phenyl ether, we can use the Williamson synthesis method, which involves the reaction of an alkoxide with a primary halide. Here’s a step-by-step breakdown of how to arrive at the correct answer:

### Step 1: Understand the Structure of Allyl Phenyl Ether
Allyl phenyl ether consists of an allyl group (CH2=CH-CH2) bonded to a phenyl group (C6H5) through an oxygen atom. The general structure can be represented as:
\[ \text{C6H5-O-CH2-CH=CH2} \]

### Step 2: Identify the Reactants
To synthesize allyl phenyl ether, we need:
1. An alkoxide (which can be sodium phenoxide, C6H5O^-Na^+).
2. A primary halide that contains the allyl group (for example, allyl bromide, CH2=CH-CH2Br).

### Step 3: Williamson Synthesis Reaction
In the Williamson synthesis, the alkoxide ion attacks the carbon atom of the primary halide, leading to the formation of the ether and the elimination of a halide ion (Br^- in this case).

### Step 4: Analyze the Given Options
- **Option A: Aryl bromide (C6H5Br)** - This is not a primary alkyl halide and will not undergo the Williamson synthesis.
- **Option B: Allyl bromide (CH2=CH-CH2Br)** - This is a primary halide and can react with sodium phenoxide to form allyl phenyl ether.
- **Option C: C6H5CH=CHBr** - This is not a primary halide and will not yield allyl phenyl ether.
- **Option D: CH2=CHBr (vinyl bromide)** - This will not yield allyl phenyl ether as it does not contain the correct structure for the desired product.

### Step 5: Conclusion
The correct reactants to prepare allyl phenyl ether through heating are found in **Option B** (Allyl bromide with sodium phenoxide).

### Final Answer:
Allyl phenyl ether can be prepared by heating allyl bromide (CH2=CH-CH2Br) with sodium phenoxide (C6H5O^-Na^+).

---