`ClCH_2CH_(2)OH` is stronger acid than `CH_(3)CH_(2)OH` because of :

Options

A. `-I` effect of Cl increases negative charge on O atom of alcohol.
B. `-I` effect of Cl disperses negative charge on O atom to produce more stable cation.
C. `-I` effect of Cl disperses negative charge on O atom to produce more stable anion.
D. None of these.

Explanation

To determine why `ClCH₂CH₂OH` (chlor ethanol) is a stronger acid than `CH₃CH₂OH` (ethanol), we need to analyze the stability of the conjugate bases formed when these compounds donate a proton (H⁺).

### Step-by-Step Solution:

1. **Identify the Acids**:
- The two acids in question are `ClCH₂CH₂OH` and `CH₃CH₂OH`.
- When these acids donate a proton (H⁺), they form their respective conjugate bases: `ClCH₂CH₂O⁻` and `CH₃CH₂O⁻`.

2. **Conjugate Base Stability**:
- The strength of an acid is determined by the stability of its conjugate base. The more stable the conjugate base, the stronger the acid.
- For `ClCH₂CH₂OH`, the conjugate base is `ClCH₂CH₂O⁻`.
- For `CH₃CH₂OH`, the conjugate base is `CH₃CH₂O⁻`.

3. **Effect of Substituents**:
- In `ClCH₂CH₂O⁻`, the chlorine atom (Cl) is an electronegative atom and exerts a -I (inductive) effect. This means it pulls electron density away from the oxygen atom in the conjugate base, which stabilizes the negative charge on the oxygen.
- In contrast, in `CH₃CH₂O⁻`, the methyl group (CH₃) has a +I (inductive) effect, which pushes electron density towards the oxygen atom, increasing the negative charge and making the conjugate base less stable.

4. **Comparison of Stability**:
- The conjugate base `ClCH₂CH₂O⁻` is more stable because the -I effect of Cl reduces the negative charge on the oxygen atom, while `CH₃CH₂O⁻` is less stable due to the +I effect of the alkyl group, which increases the negative charge on the oxygen atom.

5. **Conclusion**:
- Since `ClCH₂CH₂O⁻` is more stable than `CH₃CH₂O⁻`, it follows that `ClCH₂CH₂OH` is a stronger acid than `CH₃CH₂OH`.

### Final Answer:
`ClCH₂CH₂OH` is a stronger acid than `CH₃CH₂OH` because the conjugate base `ClCH₂CH₂O⁻` is more stable due to the -I effect of chlorine, which stabilizes the negative charge on the oxygen atom, whereas the conjugate base `CH₃CH₂O⁻` is less stable due to the +I effect of the alkyl group.