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1 mole of mixture of CO and CO2 requires...

1 mole of mixture of `CO and CO_2` requires exactly 28 g KOH in solution for complete conversion of all the `CO_2` into `K_2CO_3.` How much amount more of KOH will be required for conversion into `K_2CO_3` ? If one mole of mixture is completely oxidised to `CO_2.`

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The correct Answer is:
84
`CO + 1/2 O_(2) to CO_(2)`,
`CO_(2) + 2KOH to K_(2)CO_(3) + H_(2)O`
Moles of KOH `=28/56 =0.50`
It corresponds to 0.25 mol of `CO_(2)`
Hence mol of CO `=1-0.25 = 0.75`
= moles of `CO_(2)` formed
Mol of KOH required `=2 xx 0.75 = 1.5 = 1.5 xx 56 = 84 g`
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