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6.2 g of a sample containing NaHCO(3), N...

6.2 g of a sample containing `NaHCO_(3)`, `NaHCO_(3)` and non -volatiale inert impurity on gentle heating loses 5% of its mass due to reaction `2NaHCO_(3)to Na_(2)CO_(3)+H_(2)O+CO_(2).` Residue is dissolved in water and formed 100 mL solution and its 10 mL portion requires 7.5 mL of 0.2 M aqueous solution of `BaCl_(2)` for complete precipitation of carbonates.
Determine mass (in gram) of `Na_(2)CO_(3)` in the original sample .

Text Solution

Verified by Experts

The correct Answer is:
1.06
Loss in mass due to heating `=6.2 xx 5/100 = 0.31`g
`underset(2 xx 84 g)(2NaHCO_(3)) to Na_(2)CO_(3) + CO_(2) + H_(2)O`
1 mole `NaHCO_(3) to 31` g loss due to heating 0.31 g loss from 0.01 mole of `NaHCO_(3)`
Moles of `Na_(2)CO_(3)` produced `=0.01/2=0.05`
`=(7.5 xx 0.2 xx 100/10) xx 10^(-3) = 0.015` mol
Moles of carbonate in original sample
`=0.015 - 0.05 = 0.01`
mass of `Na_(2)CO_(3)` in original sample.
`-0.01 xx 106 = 1.06`g
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