Bond angle between two hybrid orbitals is `105^@` Percentage of s-orbital character of hybrid orbital is between

Answer

21.44

Explanation

s-character oc bond angle
For 25% .v character (as in `sp^(3)` hybrid orbital), bond angle is 109.5°, for 33.3% s character (as in `sp^2` hybrid orbital), bond angle is 120° and for 50% 5 character (as in sp hybrid orbital), bond angle is 180°.
Similarly, when the bond angle decreases below 109.5°, the .v-character will decrease accordingly. Decreasing in angle = 120°-109.5°= 10.5° Decrease in 5-character = 33.3 -25 = 8.3 Actual decrease in bond angle
= 109.5°-105° = 4.5° Expected decrease in s-character
`=8.3/(10.5) xx 4.5 = 3.56%`
Thus, the S-character should decrease by about 3.56% i.e., s-character = 25 -3.56 = 21.44%