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Consider the following compounds : (i)...

Consider the following compounds :
`(i) IF_(5) " " (ii) ClI_(4)^(-) " " (iii) XeO_(2)F_(2) " " (iv) NH_(2)^(-) `
`(v) BCl_(3) " " (vi) BeCl_(2) " " (vii) AsCl_(4)^(+) " " (viii) B(OH)_(3)`
(ix) `NO_(2)^(-) " " (x) ClO_(2)^(+)`
Then calculate value of "x+y-z", here, x,y and z are total number of compounds in given compounds in which central atom used their all three p-orbitals, only two p-orbitals and only one p-orbital in hybridisation respectively .

Text Solution

Verified by Experts

The correct Answer is:
8
(i) `IF_(5)(sp^(3)d)`, (ii) `CI I_(4)^(-)(sp^(3)d^(2))`
(iii) `XeO_(2)F_(2)(sp^(3)d)`, (iv) `NH_(2)^(-)(sp^(3))`
(v) `BCl_(3)(sp^(2))`, (vi) `BeCl_(2)(sp)`
(vii) `AsCl_(4)^(+)(sp^(3))`, (viii) `B(OH)_(3)(sp^(2))`
(ix) `NO_(2)^(-)(sp^(2))`, (x) `ClO_(2)^(+)(sp^(2))`
`x=(sp^(3))2 + sp^(3) d^(1) + sp^(3)d^(2)=5`
y=4, z=1, `therefore x+y -z=5+4-1=8`
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