At 300 K, the density of a certain gaseous molecule at 2 bar is double to that of dinitrogen `(N_(2))` at 4 bar. The molar mass of gaseous molecule is:

Answer

112

Explanation

Density `(rho) = (PM)/(RT)` (1 bar = 0.987 atm) `rho_(N_(2)) = (4 xx 0.987 xx 28)/(R xx 300)`
Let the molar mass of gas b x
`rho_("gas") =(2 xx 0.987 xx x)/(R xx 300)`
Given `rho_("gas") = rho_(N_(2)) xx 2`
`(2 xx 0.987 xx x)/R xx 300 = (4 xx 0.987 xx 28)/(R xx 300) xx 2`
`therefore x = 112` g/mol