If one mole of a monoatomic gas `(gamma=5//3)` is mixed with one mole of a diatomic gas `(gamma = 7//5)` the value of `gamma` for the mixture is .

Answer

1.5

Explanation

for momentum - `C_(v) = 3/2 RT, C_(p) = 5/2 RT`
for diatomic gas
`C_(v) =5/2 2RT, C_(P) = 7/2 RT`
Thus, for mixture of 1 mole each,
`C_(v) =(3/2 RT + 5/2 RT)/(2)` and `C_(p) =(5/2RT + 7/2 RT)/2`
Thus, `C_(p)/C_(v) =(3RT)/(2RT) = 1.5`