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A mixture of Ne and Ar kept in a close...

A mixture of Ne and Ar kept in a closed vessel at 250 K has a total K.E.=3 kJ. The total mass of Ne and Ar is 30 g. Find mass % of Ne in gaseous mixture at 250 K.

Text Solution

Verified by Experts

The correct Answer is:
28.3
`K=3/2n_(T)RT rArr n_(T) = (3000 xx 2)/(3 xx 250 xx 8.314)`
`=3 xx 10^(3) = 3/2 n_(T) xx 8.314 xx 250`
`x/20 + (30-x)/40 = 2/(8.314)`
% Ne = 28.3
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