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What is the compressibility factor (Z) f...

What is the compressibility factor (Z) for 0.02 mole of a van der Waals's gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible.
Given : RT=20 L atm `mol^(-1)` and a=1000 atm `L^(2) mol^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
0.5
`(0.1 + (1000 xx (0.02)^(2))/V^(2))V = 20 xx 0.02`
`0.1 V^(2) - 0.4 V + 0.4=0`
`V^(2) - 4V + 4=0`
`Z = (PV)/(nRT) = (0.1 xx 2)/(20 xx 0.02) = 0.5`
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