Home
Class 12
CHEMISTRY
28 g N2 and 6.0 g of H(2) are heated ov...

28 g N2 and 6.0 g of `H_(2)` are heated over catalyst in a closed one litre flask of 450 °C. The entire equilibrium mixture required 500 mL of 1.0 M `H_(2)SO_(4)` for neutralisation. Calculate the value of Kc in `L^(2) "mol"^(2)` for the given reaction.
`N_(2)(g) + 3H_(2)(g) to 2NH_(3)(g)`

Text Solution

Verified by Experts

The correct Answer is:
0.592
Moles of `N_(2) =28/28=1,` moles of `H_(2)=6/2=3`
Moles of `H_(2)SO_(4)` required `=(500 xx 1)/1000 =0.5`
Moles of `NH_(3)` neutralised by `H_(2)SO_(4)=1.0`
`2NH_(3) + H_(2)SO_(4) to (NH_(4))_(2)SO_(4)`
Hence 1 mole of `NH_(3)` by the reaction between `N_(2)` and `H_(2)`
`{:(N_(2),+,3H_(2), `K_( c) =(1 xx 1)/(0.5 xx (1.5)^(3)) = 0.592 mol^(-2) L^(2)`
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE NUMERIC/INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER-8: REDOX REACTIONS|15 Videos

  • CHAPTERWISE NUMERIC/INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER-12: ORGANIC CHEMISTRY- SOME BASIC PRINCIPLES AND TECHNIQUES|15 Videos

  • CHAPTERWISE NUMERIC/INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise Chapter-6: THERMODYNAMICS|15 Videos

  • BIOMOLECULES

    DISHA PUBLICATION|Exercise Exercise - 2 : Concept Applicator|30 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT APPLICATOR|30 Videos

Similar Questions

Explore conceptually related problems

28 g N_2 and 6.0 g of H_2 are heated over catayst in a closed one litre flask of 450^@C . The entire equilibrium mixture required 500 mL of 1.0 MH_2SO_4 for neutralisation. The value of K_c for the reaction N_2(g)+3H_2(g)hArr2NH_3(g) is

The value of K_c for the reaction N_(2(g))+ 3H_(2(g)) Leftrightarrow 2NH_(3(g)) depends on

If Delta_(f)G^(@) for NH_(3)(g) is -16.4 kJ "mol"^(-1) , then DeltaG^(@) for the reaction: N_(2)(g) + 3H_(2)(g) to 2NH_(3)(g) is

Increased pressure shifts the equilibrium of the reaction: N_(2)(g)+3H_(2)(g)harr2NH_(3)(g) so as to

28g of N_2 and 6g of H_2 were mixed. At equilibrium 17g of NH_3 was formed. The weight of N_2 and H_2 at equilibrium are respectively

28 g of N_(2) and 6 g of H_(2) were kept at 400^(@)C in 1 litre vessel, the equilibrium mixture contained 27.54 g of NH_(3) . The approximate value of K_(c) for the above reaction can be ("in mole"^(-2) "litre"^(2))