Home
Class 12
CHEMISTRY
Calculate the pH at the equivalence poin...

Calculate the pH at the equivalence point when a solution of 0.01 M `CH_(3)COOH` is titrated with a solution of 0.01 M NaOH.pKa of `CH_(3)COOH` is 4.74

Text Solution

Verified by Experts

The correct Answer is:
8.22

`CH_(3)COOH + NaOH Let acid be = V mL
VmL of 0.01 M `CH_(3)COOH` will require V ml of 0.01 mL NaOH. But `CH_(3)COONa` formed will make solution alkaline due to hydrolysis
`CH_(3)COONa = 0.01/2 = 0.005` M
Using equation for pH of salt of weak acid and strong base.
`pH = 7 + (pK_(a))/2 + (log C)/2 = 7 + (4.74)/2 + (log 0.005)/2`
= 8.22
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE NUMERIC/INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER-8: REDOX REACTIONS|15 Videos
  • CHAPTERWISE NUMERIC/INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER-12: ORGANIC CHEMISTRY- SOME BASIC PRINCIPLES AND TECHNIQUES|15 Videos
  • CHAPTERWISE NUMERIC/INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise Chapter-6: THERMODYNAMICS|15 Videos
  • BIOMOLECULES

    DISHA PUBLICATION|Exercise Exercise - 2 : Concept Applicator|30 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT APPLICATOR|30 Videos

Similar Questions

Explore conceptually related problems

Calculate the pH at the equivalence point when a solution of 0.01 M CH_3COOH is titrated with a solution of 0.01 M NaOH. pK_a of CH_3COOH is 4.74.

Calculate the pH at the equivalence point when a solution of 0.1 M CH_3COOH is titrated with a solution of 0.1 M NaOH. K_a(CH_3COOH)= 1.8 xx 10^(-5)

Calculate the pH at the equivalence point when a solution of 0.1 M acetic acid is titrated with a solution of 0.1 M NaOH. K_(a) for acid =1.9xx10^(-5) .

Calculate the pH at the equivalence point during the titration of 0.1M, 25 mL CH_(3)COOH with 0.05M NaOH solution. [K_(a)(CH_(3)COOH) = 1.8 xx 10^(-5)]

Calculate the pH of each of the following solution (i) 100 ml of 0.1 M CH_(3)COOH mixed with 100 ml of 0.1 M NaOH. (ii) 100 ml of 0.1 M CH_(3)COOH mixed with 50 ml of 0.1 m NaOH (iii) 50 ml of 0.1 M CH_(3)COOH mixed with 100 ml of 0.1 M NaOH. K_(a)(CH_(3)COOH)=1.8xx10^(-5)

CH_(3)COOH is titrated with NaOH solution. Which is true statement?

The pH of a 0.1 M CH_(3)COOH which is 2% ionised in aqueous solution is

pH when 100 mL of 0.1 M H_(3)PO_(4) is titrated with 150 mL 0.1 m NaOH solution will be :