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At a certain temperature and 2 atm press...

At a certain temperature and `2` atm pressure equilibrium constant `(K_(p))` is `25` for the reaction
`SO_(2)(g)+NO_(2)(g)hArrSO_(3)(g)+NO(g)`
Initially if we take `2` moles of each of the four gases and `2` moles of inert gas, what would be the equilibrium pparital pressure of `NO_(2)`?

Text Solution

Verified by Experts

The correct Answer is:
0.134
`underset(2-x)underset(2)(SO_(2)(g)) + underset(2-x)underset(2)(NO_(2)(g)) Total no. of moles of gases at equilibrium
=8+2=10
`K_(P) =(P_(SO_(3)).P_(NO))/(P_(SO_(2)).P_(NO_(2)))`
`rArr 5 =(2+x)/(2-x), x=1.33`
Partial Pressure of `NO_(2) = (2-x)/10 xx P_("total")`
`=0.67/10 xx 2 = 0.134` atm
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