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When K(2)Cr(2)O(7) is converted to K(2)C...

When `K_(2)Cr_(2)O_(7)` is converted to `K_(2)CrO_(4)`, the change in the oxidation state of chromium is

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O.N. of Cr in `K_(2)Cr_(2)O_(7): 2 + 2x -14=0`
`2x =12, x=6`
O.N. of Cr in `K_(2)CrO_(4) : 2 + x-8=0`
x=6
`therefore` Change in O.N. of Cr = 6-6=0
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